Integrand size = 19, antiderivative size = 75 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=-\frac {\cos (c+d x)}{a^3 d}-\frac {1}{2 a d (a+a \cos (c+d x))^2}+\frac {3}{d \left (a^3+a^3 \cos (c+d x)\right )}+\frac {3 \log (1+\cos (c+d x))}{a^3 d} \]
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Time = 0.16 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {3957, 2912, 12, 45} \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=-\frac {\cos (c+d x)}{a^3 d}+\frac {3}{d \left (a^3 \cos (c+d x)+a^3\right )}+\frac {3 \log (\cos (c+d x)+1)}{a^3 d}-\frac {1}{2 a d (a \cos (c+d x)+a)^2} \]
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Rule 12
Rule 45
Rule 2912
Rule 3957
Rubi steps \begin{align*} \text {integral}& = -\int \frac {\cos ^3(c+d x) \sin (c+d x)}{(-a-a \cos (c+d x))^3} \, dx \\ & = \frac {\text {Subst}\left (\int \frac {x^3}{a^3 (-a+x)^3} \, dx,x,-a \cos (c+d x)\right )}{a d} \\ & = \frac {\text {Subst}\left (\int \frac {x^3}{(-a+x)^3} \, dx,x,-a \cos (c+d x)\right )}{a^4 d} \\ & = \frac {\text {Subst}\left (\int \left (1-\frac {a^3}{(a-x)^3}+\frac {3 a^2}{(a-x)^2}-\frac {3 a}{a-x}\right ) \, dx,x,-a \cos (c+d x)\right )}{a^4 d} \\ & = -\frac {\cos (c+d x)}{a^3 d}-\frac {1}{2 a d (a+a \cos (c+d x))^2}+\frac {3}{d \left (a^3+a^3 \cos (c+d x)\right )}+\frac {3 \log (1+\cos (c+d x))}{a^3 d} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.37 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=\frac {\cos ^2\left (\frac {1}{2} (c+d x)\right ) \left (21-2 \cos (3 (c+d x))+72 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )+\cos (2 (c+d x)) \left (-5+24 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )\right )+\cos (c+d x) \left (22+96 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )\right )\right )}{4 a^3 d (1+\cos (c+d x))^3} \]
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Time = 0.45 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.79
method | result | size |
parallelrisch | \(\frac {-29-24 \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )-\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}-8 \cos \left (d x +c \right )+12 \sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{8 a^{3} d}\) | \(59\) |
derivativedivides | \(\frac {-\frac {1}{2 \left (1+\sec \left (d x +c \right )\right )^{2}}-\frac {2}{1+\sec \left (d x +c \right )}+3 \ln \left (1+\sec \left (d x +c \right )\right )-\frac {1}{\sec \left (d x +c \right )}-3 \ln \left (\sec \left (d x +c \right )\right )}{d \,a^{3}}\) | \(63\) |
default | \(\frac {-\frac {1}{2 \left (1+\sec \left (d x +c \right )\right )^{2}}-\frac {2}{1+\sec \left (d x +c \right )}+3 \ln \left (1+\sec \left (d x +c \right )\right )-\frac {1}{\sec \left (d x +c \right )}-3 \ln \left (\sec \left (d x +c \right )\right )}{d \,a^{3}}\) | \(63\) |
norman | \(\frac {\frac {9 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{8 d a}-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{8 d a}-\frac {13}{4 a d}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right ) a^{2}}-\frac {3 \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{a^{3} d}\) | \(90\) |
risch | \(-\frac {3 i x}{a^{3}}-\frac {{\mathrm e}^{i \left (d x +c \right )}}{2 a^{3} d}-\frac {{\mathrm e}^{-i \left (d x +c \right )}}{2 a^{3} d}-\frac {6 i c}{a^{3} d}+\frac {6 \,{\mathrm e}^{3 i \left (d x +c \right )}+10 \,{\mathrm e}^{2 i \left (d x +c \right )}+6 \,{\mathrm e}^{i \left (d x +c \right )}}{a^{3} d \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{4}}+\frac {6 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{a^{3} d}\) | \(128\) |
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Time = 0.27 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.28 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=-\frac {2 \, \cos \left (d x + c\right )^{3} + 4 \, \cos \left (d x + c\right )^{2} - 6 \, {\left (\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 4 \, \cos \left (d x + c\right ) - 5}{2 \, {\left (a^{3} d \cos \left (d x + c\right )^{2} + 2 \, a^{3} d \cos \left (d x + c\right ) + a^{3} d\right )}} \]
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\[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=\frac {\int \frac {\sin {\left (c + d x \right )}}{\sec ^{3}{\left (c + d x \right )} + 3 \sec ^{2}{\left (c + d x \right )} + 3 \sec {\left (c + d x \right )} + 1}\, dx}{a^{3}} \]
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Time = 0.20 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.95 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=\frac {\frac {6 \, \cos \left (d x + c\right ) + 5}{a^{3} \cos \left (d x + c\right )^{2} + 2 \, a^{3} \cos \left (d x + c\right ) + a^{3}} - \frac {2 \, \cos \left (d x + c\right )}{a^{3}} + \frac {6 \, \log \left (\cos \left (d x + c\right ) + 1\right )}{a^{3}}}{2 \, d} \]
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Time = 0.32 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.84 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=-\frac {\cos \left (d x + c\right )}{a^{3} d} + \frac {3 \, \log \left ({\left | -\cos \left (d x + c\right ) - 1 \right |}\right )}{a^{3} d} + \frac {6 \, \cos \left (d x + c\right ) + 5}{2 \, a^{3} d {\left (\cos \left (d x + c\right ) + 1\right )}^{2}} \]
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Time = 0.09 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.79 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^3} \, dx=\frac {3\,\ln \left (\cos \left (c+d\,x\right )+1\right )}{a^3\,d}-\frac {\cos \left (c+d\,x\right )}{a^3\,d}+\frac {3\,\cos \left (c+d\,x\right )+\frac {5}{2}}{a^3\,d\,{\left (\cos \left (c+d\,x\right )+1\right )}^2} \]
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